How Do You Apply Kirchhoff's Rules to a Series Circuit with Multiple Resistors?

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To apply Kirchhoff's rules to a series circuit with multiple resistors, start by identifying the total current and the voltage across each resistor. The current splits at junctions, so use the relationship I1*R1 = I2*R2 to analyze the current through each resistor. Calculate the total current using the formula TotalCurrent = Voltage/RAB, where RAB is the equivalent resistance at the junction. Ensure that the sum of the currents entering and leaving any junction equals zero, as per Kirchhoff's current law. This approach will help clarify the voltage and current distribution in the circuit.
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Homework Statement


http://img165.imageshack.us/img165/3182/73661395nq3.jpg
http://g.imageshack.us/img165/73661395nq3.jpg/1/


Homework Equations


V = IR


The Attempt at a Solution


I got the first part right, but the second part eludes me.

V = IR
I = V/R
I = 46.3 / 7.05
I = 6.567375887 A

Which seems way too simple and wrong anyway.
I'm not really sure how to analyze the voltage or the current when it splits at the 1.75 and 7.05 ohm junction. How would I apply Kirchoff's rules here?
 
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Arriving at that junction the current sees a 7.05 Ohm resistor (R1) and a resistance RAB (R2) which you calculated already.
So the current will split as I1*R1 = I2*R2
You know R1 and R2.
You know I1 + I2 = TotalCurrent.
And you know TotalCurrent = Voltage/RAB
 
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