How do you calculate current in a changed parallel circuit?

AI Thread Summary
In a changed parallel circuit, the total current is affected by changes in resistance, even if the voltage remains constant. When resistances are equal and one branch is removed, the circuit effectively has fewer branches, altering the total current. The calculation involves understanding that current divides among the branches, so removing one branch changes the distribution. The discussion emphasizes that the current must be recalculated based on the new configuration of the circuit. Understanding these principles is crucial for accurately determining current in parallel circuits.
bobtheubs
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Well this is my question, its not really homework or anything. I am just curious as to how you would do this. I was thinking that it would change at all. Since in a parallel circuit all the currents add up to the same number. So wouldn't you just divide 24 by 4, then minus 6 from the total I. Then times that by 3 and there you go. Thanks.
 
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Could you write out the question please? I can't read that!
 
Your voltage didn't change, but your resistance changed, so the current has to change.

The picture is hard to read, but I take it all the resistances are equal and the circuit is broken at P?

If so, you now have a parallel circuit with three branches instead of four. If you work both equations using R and simplify, the difference between them should be pretty obvious.
 
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