How Do You Calculate E in Mica for a Capacitor?

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To calculate the electric field (E) in mica for a parallel-plate capacitor with a capacitance of 60 pF and a dielectric constant of 5.4, the formula E = [Q/A]/(k*Eo) is used, but the initial calculation provided was incorrect. The charge (Q) on the plates is determined using Q = C * V, resulting in 1e-12 C. The user expressed difficulty in obtaining the correct value for E, indicating a need for further resources or assistance. The discussion highlights the importance of accurately applying formulas and checking calculations when working with capacitors and dielectrics. Accurate calculations are essential for understanding capacitor behavior in electrical applications.
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A parallel-plate capacitor has a capacitance of 60 pF, a plate area of 130 cm2, and a mica dielectric ( = 5.4). At 60 V potential difference, calculate the following values.

(a) E in the mica
wrong check mark V/m
(b) the magnitude of the free charge on the plates
C
(c) the magnitude of the induced surface charge on the mica
C

I tried the following:
E = [Q/A]/(k*Eo);
E = (1e-12/.013)/(5.4)(8.85e-12);
E = 1.609 which is wrong.

I got Q by the following: C = QV; Q = C/V; 60e-12/60 = 1e-12
 
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Sorry for the late reply. If you're still working on this then check out the websites I gave you in this thread and see if you don't have better luck.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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