How Do You Calculate Electric Potential?

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Homework Help Overview

The discussion revolves around calculating electric potential and electric fields in the context of electromagnetism, specifically involving a scenario with charges positioned at the corners of an equilateral triangle. The original poster presents two questions related to achieving zero electric field and zero electric potential at the center of the triangle.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between electric field and electric potential, questioning how to determine the necessary charge at the third corner of the triangle to achieve the desired conditions. There is also discussion about using trigonometry and vector addition to analyze the electric field.

Discussion Status

Some participants have offered insights into the vector nature of electric fields and the concept of electric potential as a scalar quantity. There is an ongoing exploration of the symmetry in the problem and the implications for the charge needed to achieve equilibrium at the center of the triangle.

Contextual Notes

Participants note challenges with the clarity of instruction from their lecturer and express a desire for further understanding of electromagnetism as a whole. There are references to specific equations and the need for integration or differentiation in the context of the second question.

elrohir00
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Hi,
i have 2 questions for electromagnitism and i just can't do them. my lecturer is just not up to the job of teaching and everyone is struggling and its probably something easy. anyway rant over.

1) you have an equlateral trinagle with chare q in 2 corners. what charge would you have to put into the third corner so the centre has
a)0 electric field
b)0 electric potential

in part a) what is the electric potential
in part b) what is the electic field

for this i have just been plating with trigonomatry and it just seems to longwinded for an answer that just doesn't seem right.

2) state how electric field can be calculated by electric potential.
the electric potential at derpendicular distance r from a long straight wire with cross section a is

v(r)=-k ln (r/a)

k is constant. calculate electric field as a function of r.

i know this is to do with intergrating or differentiating but not sure which.

if someone would be so kind to answer these and also give some details on elecromagnitism as a whole that would be amazing.

THANKS ALL
 
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Homework Statement


there are 2 questions to this.
1) you have a equlateral triangle with 2 charged particles q in the corners. by choseing the third particle make the centre of the triangle have 0
a)field
b)porential
in case a what is the potential in case b what is the field.


Homework Equations


my lecturer isn't the best in the world but i think these are the formulae
E=q/r
v=q^2/r
some trig?


The Attempt at a Solution



i have just been playing around with trig to get the r value then doubling it as there are 2 charge q then thring to exuate it to a mystery charge.

thanks for any insite I am going off to get a book to try and help me along with this as my lecturer is just not worth while
 
Let's start with question (a). Can you write an expression for the electric field at the centre of the triangle in terms of their charges and position?
 
The electric field is a vector field and the total vector field is found by vector addition. Find the fields magnitude and direction due to the first two charges and work out what charge you will need to cancel it out. Electric potential due to a load of point charges is just the sum due to the individual point charges.

For part 2, remember that a conservative vector field is the gradient of a scalar potential function.
 
I merged the two threads, based on thread titles and problem statement.
 
ok i think for a

the charge will be q due to symetry
the distance r between to corner and centre is the same so if the extra one has the same charge it will just all cancal out.

b)

0=kq/r+kq/r+kQ/r
rearanged and simplifed
Q=-2q

now with the extra charges the rest should fall into place.
 
Yes, looks ok to me.
 

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