How Do You Calculate Initial Velocity and Displacement of a Thrown Stone?

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To calculate the initial velocity of a stone thrown from a height of 80m and landing 60m away, kinematic equations must be applied for both the horizontal (x) and vertical (y) motions. Gravity acts downward in the y-direction, while horizontal motion maintains constant velocity. The time of flight can be determined using the vertical motion equation, and this time can then be used to find the initial horizontal velocity. Additionally, the discussion raises a question about the time taken for the stone to reach twice its initial velocity and its displacement at that moment. Understanding these dynamics is crucial for solving the problem effectively.
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A stone (taken as a point mass) is thrown from a cliff of height H = 80m perpendicular to the ground. It falls L = 60m away from the cliff. What is the initial velocity V with which the stone is thrown?

Obviously we have to deduce the formula for velocity using kinematic equations w/ respect to H and L. Help will be very appreciated. Thank you.
 
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siddharthmishra19 said:
A stone (taken as a point mass) is thrown from a cliff of height H = 80m perpendicular to the ground. It falls L = 60m away from the cliff. What is the initial velocity V with which the stone is thrown?

Obviously we have to deduce the formula for velocity using kinematic equations w/ respect to H and L. Help will be very appreciated. Thank you.

Think of the equations of motion for both the x and y direction. In which direction is the velocity constant? IN which direction does gravity act?
Btw, the angle of the throw is not given?
 
g acts in y direction. velocity is constand is x direction. angle of throw, as mentioned, is perpendicular to the ground, and sincs cos90 = 1 it can be neglected.

i need help solving it.
 
siddharthmishra19 said:
g acts in y direction. velocity is constand is x direction. angle of throw, as mentioned, is perpendicular to the ground, and sincs cos90 = 1 it can be neglected.

i need help solving it.
Just list what you know
a_x = 0, a_y = -9.80 m/s^2, x_i=y_i=0, x_f=60 m, y_f =-80 m, v_{yi}=0 and what you are looking for is v_x.

Just write the equations along x and along y that you will need. Notice that you will have to find the time as well. So the idea is to find the time using the y equation and then use that in the equation along x to find the velocity.
 
thanks, all done
 
In the same problem, what is the time taken by the body to attain a velocity twice its initial velocity?

What is the displacement of the body at that time?
 
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