How Do You Calculate Net Force on a Diver?

AI Thread Summary
To calculate the net force on a diver who drops from a diving board, the diver's mass is 82 kg, and he reaches a velocity of 7.6 m/s before hitting the water. The force due to gravity acting on him is calculated as 803.6 N. After entering the water, the diver comes to rest in 0.55 seconds, leading to an estimated average force exerted by the water of 1133.1 N. The discussion emphasizes the importance of understanding average acceleration and net force in this context. Overall, the calculations focus on determining the diver's dynamics during the fall and subsequent deceleration in the water.
Haley Heldt
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Homework Statement


An 82 kg man drops from rest on a diving board 3 m above the surface of the water and comes to rest .55 s after reaching the water. What is the net force on the diver as he is brought to rest

Homework Equations


FDt = mv F = mg v^2 = vi^2 = 2aDx Dx = 3m Dt = .33 s m = 82 kg g = 9.8m/s^2

The Attempt at a Solution


I have plunged the numbers into the equation and i found the velocity to be 7.6 m/s. Also I am pretty sure mg= 803.6 N I am just super confused on how to find the net force please help! thanks!
 
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What is the guy's velocity when he hits the water. What is his velocity when he stops. What is his average deceleration? What is the average net force exerted on him by the water?
 
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Chestermiller said:
What is the guy's velocity when he hits the water. What is his velocity when he stops. What is his average deceleration? What is the average net force exerted on him by the water?
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N . I know that he starts at rest and he eventually ends at rest however I don't know his average net force or deceleration. Sorry!
 
Haley Heldt said:
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
In the equation ##\int F.dt=m\Delta v##, why should F be specifically the force from the water? What other forces act?
 
If you're traveling 7.6 m/s, and 0.55 sec later, your speed is 0, what is your average acceleration?
 
Chestermiller said:
If you're traveling 7.6 m/s, and 0.55 sec later, your speed is 0, what is your average acceleration?
The way I read post #3, Haley is past that point.
Indeed, has the answer but does not realize it.
 
haruspex said:
The way I read post #3, Haley is past that point.
Indeed, has the answer but does not realize it.
Post #3: "I don't know his average net force or deceleration"
 
Chestermiller said:
Post #3: "I don't know his average net force or deceleration"
Yes, but:
Haley Heldt said:
What is the net force on the diver
Haley Heldt said:
I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
haruspex said:
why should F be specifically the force from the water?
 
haruspex said:
Yes, but:
I see what you're saying, but she really ought to know how acceleration is defined and how net force is defined (and why). It seems to me that she luckily pulled the impulse equation out of the air without really understanding what is happening at a fundamental level.

Chet
 
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