How Do You Calculate the Correct Resistor Values for a Simple Voltage Regulator?

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To design a simple voltage regulator delivering 7.00 volts from a 10V power supply, a series resistor (R1) and two parallel resistors (R2 and Rload) are used. The calculated value for R2 is 100 ohms, while R1 is determined to be 40 ohms through experimentation. The calculation for R1 involves using the formula (91/(91+R1)) * 10 = 7.0, which confirms that 40 ohms is correct. By setting Rload to 1k ohms, the current is calculated as 14mA, leading to the final calculation for R1 using Ohm's Law, resulting in a value of 214 ohms. This approach effectively demonstrates the calculations needed to determine resistor values for the voltage regulator circuit.
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I am to design a simple voltage regulator(resistors only) to deliver 7.00 volts to a load with a 10v power supply. The circuit will be 1 resistor in series with two parallel resistors. The last parallel resistor being Rload (which can vary from 1000 to 1500 ohms).

Through experiment, I found that I could use a 100 ohm resistor for R2 which would make R1 a 40 ohm resistor. My problem is determining the value for R1 through calculation.

R2 and Rload at 1000 ohms is 91 ohms. So I use the formula: (91/(91+R1)) * 10 = 7.0. Is the right in determing R1? If you plug 40 for R1 is works.

I just need calculations proving this and I think I am having algebra problems solving for R1.
 
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I think the easiest way to do this is just pick a value for Rload and set R2 to the same value. So their resistance is effectively half of one of their values. For simplicity i chose 1k ohms.

Then since you know you want the value across them to be 7 volts use ohms law to solve for the current. I = V / R. I = 7v / 500 ohms this gives 14mA.

To solve for the value of the first resistor use ohms law again in the form of R = V / I. We can do this because we know the current flowing through the series circuit and we know we want 3V across the first resistor.

R = 3V/ 14mA, R = 214 ohms.
 
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