How Do You Calculate the Force Exerted by the Pole on a Tetherball?

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To calculate the force exerted by the pole on the tetherball, consider the horizontal forces acting on the ball. The tension in the rope, calculated as 4.03 N, plays a crucial role in this analysis. Since the pole is frictionless, the force it exerts on the ball must balance the horizontal component of the tension. The vertical forces, including the weight of the ball, must also be considered to ensure equilibrium. Understanding these dynamics will lead to the correct calculation of the pole's force on the ball.
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A tetherball leans against the smooth, frictionless post to which it is attached. The string is attached to the ball such that a line along the string passes through the center of the ball. The string is 1.60m long and the ball has a radius of 0.140m with mass 0.410 kg

I already drew my free body diagram and figured out the tension on the rope against the ball to be 4.03 N I just can't figure out how they want me to find the force the pole exerts on the ball.
 
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Consider the horizontal forces acting on the ball.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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