How Do You Calculate the Landé g Factor for sd Configuration in jj Coupling?

  • Thread starter Thread starter Irid
  • Start date Start date
  • Tags Tags
    Atomic Coupling
Irid
Messages
207
Reaction score
1
This is rather a straightforward question I believe, but somehow I'm not sure about the wording of it...

Homework Statement


Calculate g value (Landé g factor) for sd configuration in jj coupling.


Homework Equations


<br /> g = 1 + \frac{J(J+1) - L(L+1) + S(S+1)}{2J(J+1)}<br />


The Attempt at a Solution


For a d electron there are two j-values: 3/2 and 5/2. And then both can couple with the s electron to give 2/2, 4/2 and 4/2, 6/2 total J. So how can I calculate the g factor, there are many possibilities, correct?
 
Physics news on Phys.org
And one more.
The normal Zeeman components of a 500nm spectral line are 0.0116nm apart in a magnetic field of 1.0T. Find the ratio (e/m) of an electron.

I think I should somehow find out what is g-value to be able to proceed, but how?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top