How Do You Calculate the Third Force in a Three-Force System?

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SUMMARY

The discussion focuses on calculating the third force in a three-force system involving a 20-kg object experiencing an acceleration of a = -8 m/s² i + 6.0 m/s² j. The known forces are F1 = 3.0 N i + 16.0 N j and F2 = -12.0 N i + 8.0 N j. To find the third force F3, participants confirm the use of Newton's second law, F = ma, and suggest setting up separate equations for the x and y components of the forces. The correct approach involves solving the equations F1 + F2 + F3 = ma for both the i and j directions.

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Homework Statement



A 20-kg object is subjected to three forces which produce an acceleration a = -8 m.s-2 i + 6.0 m.s-2 j on the object. Two of the forces are:
F1 = 3.0 N i + 16.0 N j
F2 = -12.0 N i+ 8.0 N j
Find the third force.



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The Attempt at a Solution


To be honest, I've been doing physics for the past 8 hours so I'm brain dead right now. This is my last problem on my homework. I know that F=ma, so I'm thinking maybe I have to set up an equation like (F1+F2+F3)=20a. But something about that doesn't seem right. Any help and I would be very grateful.

Thanks,
 
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You're exactly right. Use F=ma and set up two equations for the two components. Set up one equation for the i direction and one equation for the j direction. F1+F2+F3=ma, then you just need to solve for F3
 
Write separate equations for the vector components of the equation F = m*A. Here F is the net force acting on mass m, so F = F1 + F2 + F3. each of these F's have two vector components (x,y directions).

So suppose you start by looking at just the x-components. Can you write the F = m*A equation for that?
 

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