How Do You Calculate the Total Mass of a Cylinder with Variable Density?

TheSpaceGuy
Messages
25
Reaction score
0
Total mass?

Homework Statement


Find the total mass of the part of the solid cylinder x^2 + y^2 ≤ 4 such that x^2 ≤ z ≤ 9 - x^2 , assuming that the mass density is p(x, y, z) = I y I (absolute value of y).


I have heard about center of mass but this is throwing me off?

The Attempt at a Solution



Thats where the problem is.
 
Physics news on Phys.org


All you have to do is integrate p(x,y,z) over the volume of interest.
 


But how would I get the limits of integration. How about choosing x from 0 to 4 and y is x^2 to 4? z is given. Am I on the right track?
 


Did you think about this very long? x can't 4 and satisfy x^2+ y^2= 4 for any y! And I have no idea how you got "y is x^2 to 4"! What do you get if you solve x^2+ y^2= 4 for y?

Perpendicular to the z-axis, the boundary is the cylinder x^2+ y^2= 4. You could let x very from -2 to 2 and, then, for every x, y varies from -\sqrt{4- x^2} to \sqrt{4- x^2}. Or write it in polar coordinates with r going from 0 to 2, \theta from 0 to 2\pi.

For every point (x, y), the z-coordinate varies from x^2 to 9- x^2 just as you are told.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top