How Do You Calculate Vce in a Simple Transistor Circuit?

  • Thread starter Thread starter verd
  • Start date Start date
  • Tags Tags
    Transistor
AI Thread Summary
To calculate the collector to emitter voltage (Vce) in a simple transistor circuit, it is essential to accurately determine the collector voltage (Vc) and emitter voltage (Ve). The correct formula for Vce is Vce = Vc + Ve, with Ve typically being grounded in basic circuits. The discussion highlights a misunderstanding regarding the values of Vc, where it should be 6V instead of 3.3V, derived from the equation Vc = RC * Ic. Clarification is provided that VBE does not affect the Vce calculation in this context, ensuring a proper understanding of the transistor's operation. Understanding these calculations is crucial for accurate analysis in transistor circuits.
verd
Messages
144
Reaction score
0
Hi,

I'm having a bit of trouble understanding how exactly to analyze a transistor in a simple circuit... Specifically when finding the collector to emitter voltage, Vce.

I've got to be looking at this incorrectly. Below is the question and the solution. My professor worked out the part that I circled as "their" solution, and I circled what I did.

Could someone explain what I'm doing wrong?

The only equation I needed for this was:
Ic=Beta*Ib

http://synthdriven.com/images/deletable/EEN305%20-%2001.jpg
 
Last edited by a moderator:
Physics news on Phys.org
nevermind. I'm a complete retard. I Vce should be:

Vce=Vc+Ve=3.3+0.7=4v.

But I am still a bit confused about how my professor derived his equation. That looks like a good equation for Vc, not Vce... Atleast to me.

Could someone explain this to me?
 
Since the emitter is grounded, Ve is the same as Vce.
 
Oops, typo, I meant Vc same as Vce.
 
your professor calculated Vc for 6 Volts right? now walk backwards through the source to the emitter to get VCE.

So +6V - 10V = -4V, so VCE has to be 4V.

Or walk the other way from emitter to collector through the source. +10V-6V=4 Volts.

VBE which is 0.7 volts plays no role here. in your calculation you say Vc is 3.3V which is NOT correct! it is 6V because RC(2kohm) *Ic(3mA) = 6V!

hope that helps.
 

Similar threads

Replies
6
Views
1K
Replies
4
Views
3K
Replies
1
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K
Replies
2
Views
4K
Replies
1
Views
2K
Replies
4
Views
2K
Back
Top