How Do You Calculate Vector Components on an Inclined Plane?

  • Thread starter Thread starter possum30540
  • Start date Start date
  • Tags Tags
    Vector
AI Thread Summary
To calculate vector components on an inclined plane, first establish a right triangle where the hypotenuse is 5 m and the angle from the vertical is 20 degrees. The adjacent side can be found using the formula 5/(tan 20), while the perpendicular component is directly the length of the hypotenuse. The incline's angle of 35 degrees should be considered when determining the components parallel and perpendicular to the slope. A sketch is recommended to visualize the angles and relationships. Understanding these relationships is crucial for solving the problem accurately.
possum30540
Messages
17
Reaction score
1

Homework Statement



a snow-covered ski slope makes an angle of 35 degrees with the horizontal. when a ski jumper plummets onto the hill, a parcel of splashed snow projects to a maximum position of 5 m at 20 degrees from the vertical in the uphill direction. find the components of its maximum position a.) parallel to the surface and b.) perpendicular to the surface.


Homework Equations



you would construct a triangle with 20* and 5 m as the opposite side.
Then use 5/(tan20) to find the adjacent side.
Then use the pythagorean theorem to find the hypotenuse. ( I don't really know if you need this though)

The Attempt at a Solution



a.) 13m

b.) 5m
 
Physics news on Phys.org
I don't understand why no one has answered my question . . .I would really like to know if I figured this out correctly or not.
 
possum30540 said:

Homework Statement



a snow-covered ski slope makes an angle of 35 degrees with the horizontal. when a ski jumper plummets onto the hill, a parcel of splashed snow projects to a maximum position of 5 m at 20 degrees from the vertical in the uphill direction. find the components of its maximum position a.) parallel to the surface and b.) perpendicular to the surface.


Homework Equations



you would construct a triangle with 20* and 5 m as the opposite side.
Then use 5/(tan20) to find the adjacent side.
Then use the pythagorean theorem to find the hypotenuse. ( I don't really know if you need this though)

The Attempt at a Solution



a.) 13m

b.) 5m
It appears that the 5 meter position is measured from the hill along a line 20 degrees to the vertical; the 5 meter length is the hypotenuse of a right triangle, whose components are parallel and perpendicular to the incline. You need to draw a sketch and determine the angle that the 5m hypotenuse makes with the incline, so that you can find these components using trig. Treat the incline as the x axis.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top