How Do You Calculate Velocity at Equilibrium in Simple Harmonic Motion?

  • Thread starter Thread starter chazgurl4life
  • Start date Start date
  • Tags Tags
    Vibrations Waves
AI Thread Summary
To calculate the velocity at equilibrium in simple harmonic motion, the maximum velocity can be determined using the equation vmax = 2π * Amplitude * Frequency. The amplitude is known (0.16 m), and the frequency is given as 2.0 Hz. The relationship between frequency and the spring constant k is also discussed, with the formula K = (2π * Frequency)² * Mass. Additionally, the conservation of energy method can be employed to find velocity, combining kinetic and potential energy. Understanding these equations and methods is crucial for solving the problem effectively.
chazgurl4life
Messages
52
Reaction score
0
A 0.55 kg mass at the end of a spring vibrates 2.0 times per second with an amplitude of 0.16 m.
(a) Determine the velocity when it passes the equilibrium point.
I have no idea how to figure this out

i mean to figure out velocity ...we use this equstion vmax= 2pi*Amplitude* Frequency

I ahve the amplitude but no frequency..im i using the right process?
 
Physics news on Phys.org
How is the frequency of oscillation related to the spring constant k? What else determines the frequency of oscillation? Once you have k, do you have what you need to figure out the midpoint velocity? You can also do it with energy conservation (KE + PE = constant)...
 
Ok so i know that K= (2pi*freq.)^2* mass and then once i have K i can uses vmax= 2pi Af and solve for A?
 
chazgurl4life said:
Ok so i know that K= (2pi*freq.)^2* mass and then once i have K i can uses vmax= 2pi Af and solve for A?
I thought you had the amplitude and frequency already. What is the SHM equation for the motion of the object in terms of the mass, spring constant k, amplitude and frequency?

y(t) = something * sin( something * t )

And then you can get the velocity by differentiating, right? Or else just take the easy way out and use the conservation of energy method that I mentioned.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top