How Do You Convert Time into Radians and Calculate Rotational Acceleration?

  • Thread starter Thread starter Stevo11
  • Start date Start date
  • Tags Tags
    Rotational
AI Thread Summary
The discussion focuses on converting time into radians and calculating rotational acceleration. Key calculations include converting the hour hand's motion over 4.4 hours to 2.3 radians and Earth's rotation over 28.5 hours to 7.5 radians. A flywheel's angular acceleration was found to be -18.18 rad/s², with it turning 198 radians before stopping and completing 31.5 cycles during the deceleration. The user expressed frustration with the material and sought additional resources for understanding rotational work. Ultimately, they successfully solved their problems with assistance from another forum member.
Stevo11
Messages
17
Reaction score
0
Rotational Accel/Radians <<Solved>>

Homework Statement



Question 1)
18. Convert the following measurements to radians.

c) the motion of an hour hand in 4.4 h = 2.3 Rad
d) Earth’s rotation in 28.5 h = 7.5 Rad

<<<<<<figured it out, thanks SammyS for that obivious yet overlooked detail lol :D >>>>>>>>

Question 2)
A flywheel rotating at 18.0 rad/s slows to a
stop in 22.0 s. Find

a) its angular acceleration. = -18.18rad/sec^2
b) the number of radians it turns before
stopping. 198 rads
c) the number of cycles it completes in
this time. 31.5 Cycles
d) the angular speed after 8.7 s. 11rads/sec

though i have a feeling this isn't the end of my issues lol, if anyone knows of an awsome site/article anything on rotational work please let me know, because I've been searching lol

Thanks sammyS

-stevo
 
Last edited:
Physics news on Phys.org
How many radians does the hour hand pass through in 12 hours?

(Problem written BDC - Before Digital Clocks!) LOL
 
Stevo11 said:

Homework Statement

Question 2)
A flywheel rotating at 18.0 rad/s slows to a
stop in 22.0 s. Find

a) its angular acceleration. = -18.18rad/sec^2
b) the number of radians it turns before
stopping.
c) the number of cycles it completes in
this time.
d) the angular speed after 8.7 s.

The Attempt at a Solution



A)found the angular acceleration,(-.818 rad/sec/sec) but I can't figure out the rest of it...

B) I tried 18*22 to get the Rads before stopping, but that didn't work...
22 rad/s is the initial ang. vel. (It's not rotating at that rate the whole time.) The final ang. vel. is zero. Assuming a constant angular acceleration, what is the Average angular velocity? Use that. Then for (C), I would simply convert radians to cycles: 1 Cycle = 2π radians.
C) I tried dividing 18/6.28 to get the Cycles/second then multiplying by 22 seconds.. but that's not right either

D) well I don't know where to start... :bugeye:

I tried a lot of different things to solve these questions, most of my efforts are scribbled on papers littered around my room lol. I'm just so extremely frustrated and need some help/guidance, I don't want to be spoon fed though (I don't learn that way), just a nice push would help, or show me an example done? those are always best for me to learn, but I can't find any "like" examples of close problems.

This is our final Unit in Classical physics and my teacher's a..well let's not go there, he can't teach at all, so we're left to our own devices... I am so hopelessly lost its painful. I know what a radian is (from calculus) and I know that 2pi is one cycle, but I've never had so much issue with anything in physics before... :mad:
(My students have claimed to have the same problem.)

Kinematic equations are much like kinematic equations for linear motion (constant acceleration):

v=v_0+a\,t\quad\leftrightarrow\quad \omega=\omega_0+\alpha t

x-x_0=v_{avg}\ t=v_0\ t+(1/2)a\,t^2\quad\leftrightarrow\quad \theta-\theta_0=\omega_{avg}\ t=\omega_0 t+(1/2)\alpha t^2

v_{avg}=\frac{v+v_0}{2}\quad\leftrightarrow\quad\omega_{avg}=\frac{\omega+\omega_0}{2}

v^2={v_0}^2+\,2\,a(x-x_0)\quad\leftrightarrow\quad\omega^2={\omega_0}^2+\,2\,\alpha(\theta-\theta_0)
 
OH wow I solved it all! thank you SOOO much Sammys! how about you replace my teacher? haha! really though thank you so much for such a speedy and helpful response, much appreciated :D!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top