How Do You Convert Weight to Newtons in Variable Gravity?

AI Thread Summary
To convert weight to Newtons in variable gravity, the equation w=mg is used, where w is weight in Newtons, m is mass in kilograms, and g is the acceleration due to gravity. In the context of the discussion, a weight of 10 kg indicates a force equivalent to 10 kg under Earth's gravity, which is approximately 98 N. The user attempted to calculate the unknown gravity by setting up the equation 10 kg = 72.5 kg * a, leading to a calculated gravity of 0.13 g. The clarification provided indicates that the weight of 10 kg refers to the force experienced in a different gravitational context. Understanding this relationship helps in accurately converting weight to Newtons in varying gravitational conditions.
Mecia22
Messages
9
Reaction score
0
dss

Homework Statement


In Rendezvous with Rama, they are on rung 700, so about 213 m down into the ship. The gravity is very small. It says that they weigh 10 kg in that gravity. So what gravity are they in?

Homework Equations



I know I use w=ma, but how do I get the 10 kg into N? I guessed that an average male weighs 72.5 kg

The Attempt at a Solution



I tried doing 10=72.5a
a=.13

But I know that weight needs to be in N, but I'm confusing myself as to how to do that in an unknown gravity.

Edit: post restored after being deleted by OP
 
Last edited by a moderator:
Physics news on Phys.org
When it says they weigh 10kg, it means that the force of gravity on them is the same as for a 10kg mass in Earth's surface gravity, i.e. 10g N.
 
So you're saying I'd do:
10kg * 10 (gravity on Earth)=72.5a ??
 
Last edited by a moderator:
Mecia22 said:
So you're saying I'd do:
10kg * 10 (gravity on Earth)=72.5a ??
Yes.
 
xcsfa
 
Last edited:
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top