How Do You Determine the Time Evolution of a Wave Function Given \(\psi(x,0)\)?

atomicpedals
Messages
202
Reaction score
7
I'm getting bogged down in what is probably a very basic subject and it's holding me back. I'm not really sure how to determine the wave function \psi(x,t) given a function \psi(x,t=0); and since this is pretty much the under-pinning of every homework problem I've seen so far it's a huge issue for me. Can anyone explain, at least generally, how I get from one to the other?
 
Physics news on Phys.org
The Schrodinger equation tells you how the state evolves over time. Your textbook should cover this.
 
The book does, but I'm coming up short with applying it beyond the limited example in the text.

So I understand (at least intellectually) for a particle in an infinite square well (between say 0 and a) I find the normalization constant and then the nth coefficient via integration from 0 to a. How do I go from this simple situation to the more general free particle of mass m? Is it simply a matter of adjusting my limits of integration?

(I promise, I'm not trying to get something for nothing with this question)
 
Sorry, it's not clear at all to me what your question is. Could you please elaborate?
 
Sorry, my own lack of clarity isn't helping...

The general solution can be found as a superposition of eigenfunctions

\psi(x,t)=\sumcn\psine-i/\hbarEt

how do I apply this to a given situation? If I start with \psi(x,0)=ei/h px , I should arrive at \psi(x,t)=ei/h (px-p2/2m t)

how did I get from point a to point b?
 
The Hamiltonian for a free particle is \hat{H}=\hat{p}^2/2m. Apply it to \psi(x,0), which is an eigenstate of \hat{H}, to find E.
 
Hmm, I agree with your explanation of Time Evolution of a Wave Function. I feel that any other explanation would be Shallow and Pedantic. Are you referring to a particle in a square well?
 
atomicpedals said:
Sorry, my own lack of clarity isn't helping...

The general solution can be found as a superposition of eigenfunctions

\psi(x,t)=\sumcn\psine-i/\hbarEt

how do I apply this to a given situation? If I start with \psi(x,0)=ei/h px , I should arrive at \psi(x,t)=ei/h (px-p2/2m t)

how did I get from point a to point b?

You are already there. If the time-independent Hamiltonian is H(\hat{p},\hat{x}) and its eigenstates are \varphi_n with energy E_n. Then each will evolve in time by only acquiring a phase factor related to its energy \varphi_n \to \varphi_n e^{-it E_n}.

So suppose you state start out at t=0 as some linear superposition of \varphi_n: \psi (0) = \sum_{n} c_n(0) \varphi_n, at time t later. Each of the states evolves independently: \psi(t) = \sum_{n} c_n(0) e^{-i t E_{n}} \varphi_n. Or another way of stating this, the coefficients of linear superposition change like this c_n(0) \to c_n (0) e^{-i E_n t}

The job is therefore to expand any general initial state into linear combination of energy eigenstates of the Hamiltonian.
 
Back
Top