How Do You Determine Voltage at a Node Using KCL?

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To determine voltage at a node using Kirchhoff's Current Law (KCL), the sum of currents entering a node must equal the sum of currents leaving that node. At node e, the correct KCL equation should account for all currents, including those passing through resistors. The current ix and 0.5ix are indeed entering node e, but the total current also includes the current through the resistors connected to node e. Clarification on the placement of voltage signs across resistors is essential for accurate calculations. Understanding these principles is crucial for solving the homework problem effectively.
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http://img.photobucket.com/albums/v405/RagingCamel/viewer.png

I'm trying to answer the steps on this homework but have no idea what i am doing.

For the first step, at node e the KCL equation would just be ix+0.5ix=0?

Since ix and 0.5ix are both entering the node of e?

Also, where are the + and - signs placed on the resistors?
 
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Chandasouk said:
http://img.photobucket.com/albums/v405/RagingCamel/viewer.png

For the first step, at node e the KCL equation would just be ix+0.5ix=0?

Since ix and 0.5ix are both entering the node of e?

No, this is not right. Sum of currents entering a node = Sum of currents leaving a node. 1.5ix=current passing the 10ohm resistor which is not zero.
 
How do I find what is entering/leaving node e?

From node c i see current i_x goes through 2 ohms, reaches node d and splits into two paths, one heading towards node b and the other across resistor 3 ohms. So, the current through 3 ohms is entering node e?

I'm pretty lost as to what to do
 

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