How Do You Differentiate the Power Series g(x) = Σ 2x²ⁿ?

blak97
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Homework Statement


Explicitly compute the function g defined by:
g(x) = \Sigman2x2n from n=1 to infinity


I was thinking something along the lines of differentiating\Sigma x2n twice
 
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Yes. So what do you get??
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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