How Do You Formulate a Vector Equation for a Plane Given Points and Directions?

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To formulate a vector equation for a plane given a point and direction vectors, start with the point (-5, 9, -3) and the direction vectors from the two lines provided. The direction vectors are [4, -1, -3] and [1, 6, -8], which can be used to define the plane. The general vector form of the plane can be expressed as r = (x_0 + As + Bt)i + (y_0 + Cs + Dt)j + (z_0 + Es + Ft)k, where (x_0, y_0, z_0) is the point in the plane and A, B, C, D, E, and F are components of the direction vectors. By substituting the given point and direction vectors into this formula, the vector equation for the plane can be accurately constructed.
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Homework Statement





Write a vector and parametric equation for a plane that:

b) contains (-5,9,-3) and is parallel to [x,y,z] = [1, -2, 7] + s[4, -1, -3] and

[x,y,z] = [7,-2,15] + t[1,6,-8]



The Attempt at a Solution


I'm not sure where to start. Usually, when asking for parallel lines, I find if the direction vectors are scalar multiples of each other, then I find out if s and t have the same value for all x y and z.



I'm confused about planes.
What they had as the answer was the exact same direction vectors s and t, and then the point given as r nought.
 
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The vector form for a plane is
\vec{r}= (x_0+ As+ Bt)\vec{i}+ (y_0+ Cs+ Dt)\vec{j}+ (z_0+ Es+ Ft)\vec{k}
where (x_0, y_0, z_0) is any point in the plane and
A\vec{i}+ C\vec{j}+ E\vec{k}
and
B\vec{i}+ D\vec{j}+ F\vex{k}
are two vectors in the plane.

In your question, you are given all three of those things.
 
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