How Do You Integrate -e^(-|x|) Over All Real Numbers?

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To integrate -e^(-|x|) over all real numbers, the integral can be split into two parts: from negative infinity to 0 and from 0 to positive infinity. The first integral evaluates to -1, while the second integral also evaluates to -1, resulting in a total of -2. The symmetry of the function around the y-axis allows for the simplification of the calculation by doubling the integral from 0 to infinity. Understanding the behavior of the function at 0 is crucial for correctly setting up the integrals. The final result confirms that the integral evaluates to -2.
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1. Homework Statement and equations
Find \int -1e-|x| between negative infinity and positive infinity.

2. The attempt at a solution

So I tried to just integrate using laws for logarithmic equations and got:
e-|x| between negative infinity and positive infinity.
Of course this leaves me with:
e-∞-e-∞ = 0
I know the answer is -2, but I am not sure how to get there. Help would be much appreciated.
 
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Try splitting the integral into two separate integrals over two separate domains.

Use the fact that |x| = -x when x<0 and |x|=x for x>0.
 
Thanks danago, I think i figured it out. I split the integral and added the integral of the function from 0 to infinity with -infinity to 0. The first one came out to -1 and the next came out to 1 respectively, giving me -2. I fail to see how I should have caught this before though since the function is defined at 0. I guess you could see that is symmetric and just double the integral from 0 to infinity?
 
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