How does a black body emit as much energy as it absorbs?

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SUMMARY

A black body absorbs all incident electromagnetic radiation, including visible light, and emits infrared (IR) radiation. The equilibrium is achieved when the energy absorbed equals the energy emitted, described by the equation Ein = Eout. Despite the higher energy of visible light photons, a black body can emit a greater number of lower-energy IR photons, maintaining energy balance. If a black body absorbs more energy than it radiates, its temperature increases until equilibrium is reached.

PREREQUISITES
  • Understanding of electromagnetic radiation and its spectrum
  • Familiarity with the concept of black body radiation
  • Knowledge of the equations E = hv and v = C/l
  • Basic principles of thermodynamics related to equilibrium
NEXT STEPS
  • Research Planck's Law for black body radiation
  • Explore the Stefan-Boltzmann Law and its applications
  • Learn about the relationship between temperature and emitted radiation
  • Investigate real-world applications of black body concepts in thermal imaging
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Students studying physics, particularly those focusing on thermodynamics and electromagnetic theory, as well as professionals in fields related to optics and thermal engineering.

GM Jackson
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Homework Statement


A black body absorbs all incident electromagnetic radiation, including visible light which has wavelengths from 380nm to 750nm. IR radiation has wavelengths that are so long they are measured in microns. That suggests that visible light has a higher frequency than IR, and, higher energy. So when a black body absorbs visible light and emits IR, how does it achieve equilibrium?

Homework Equations


Ein = Eout (Energy in = Energy out)
E = hv (E = Energy; h = 6.63E-34 J-s; v = frequency in hertz)
v = C/l (C = 3.00E8 m/s; l = wavelength in meters)

The Attempt at a Solution


I'm picturing in my mind the same amount of photons going in as going out, but this would imply more energy going in than going out. So what's up with the black body?
 
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GM Jackson said:

The Attempt at a Solution


I'm picturing in my mind the same amount of photons going in as going out, ..?

That's the problem. Far more low-energy photons are emitted, so the total in and out energy balance.
 
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GM Jackson said:
I'm picturing in my mind the same amount of photons going in as going out, but this would imply more energy going in than going out. So what's up with the black body?
Regardless of the number of photons involved, suppose the black body is absorbing more energy than it's radiating. It's not in equilibrium with its surroundings. What happens to the temperature of the black body?
 
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marcus said:
That's the problem. Far more low-energy photons are emitted, so the total in and out energy balance.
Thanks.
 
vela said:
Regardless of the number of photons involved, suppose the black body is absorbing more energy than it's radiating. It's not in equilibrium with its surroundings. What happens to the temperature of the black body?
I heard it goes up. Thanks for the input.
 
The way the question is worded implies that the blackbody isn't in equilibrium with its surroundings initially (otherwise it wouldn't have to do anything to achieve equilibrium), so it's not safe to assume the number of IR photons emitted is enough to maintain the energy balance. If you haven't already, you should consider what happens when the temperature of the blackbody goes up.
 
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