How Does a Cylinder Equation x² + y² = 2ay Represent Its Shape in 3D?

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Homework Statement



I have to find the volume of the region bounded by a cone and cylinder. (double integral style!)
I usually start off with a sketch, but I can't seem to figure out what this one quadratic surface looks like...

It's a cylinder (in 3-dimensional plane): x2+y2=2ay


The Attempt at a Solution



I know that the equation of a cylinder is just x^2+y^2=a in 3-d. I also know the equations of a hyperbolic, oblique, and parabolic cylinder...but I don't think this is one of those.
Anyone willing to help me out, or at least point me in some sort of direction!
Thanks.
 
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Try rewriting the equation into standard form:

x^2+y^2=2ay
\Rightarrow x^2+y^2-2ay=0
\Rightarrow x^2+(y-a)^2-a^2=0
\Rightarrow x^2+(y-a)^2=a^2

Which is the equation of a cylinder of radius a centered at (0,a) running parallel to the z-axis.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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