How Does Block 1's Acceleration Compare to Block 2's in a Dual Pulley System?

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In a dual pulley system, the acceleration of block 1 (a1) is twice that of block 2 (a2), expressed as a1 = 2a2. This relationship arises from the constraint of the cord's total length remaining constant as the blocks move. When block 1 moves a distance δ1 to the right, block 2 and the lower pulley move down by a distance δ2, leading to the equation δ1 = 2δ2. The kinematics of the system dictate this acceleration relationship due to the configuration of the pulleys and the cord. Understanding this principle is essential for solving related problems in mechanics.
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In the figure below, the pulleys and the cord are light, all surfaces are frictionless, and the cord does not stretch.

http://awesomescreenshot.com/0301qqz07c

How does the acceleration of block 1 compare with the acceleration of block 2? (Use the following as necessary: m1, m2, and a2.)

Explain your answer.I know that a_1 should be 2a_2 but I have no idea why. Can someone please explain in details why its like that?
 
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This is strictly a kinematics problem. Let the initial lengths of the 3 sections of cord be l1, l2, and l3, where
l1 is the initial distance between m1 and the first pulley
l2 is the distance of the first pulley above the second pulley
l3 is the distance of the second pulley below the ceiling

Let m1 move to the right by δ1 and let m2 (and the lower pulley) move down by δ2. Now, the new lengths of the 3 sections of cord are l11, l2 + δ2, l3 + δ2. The total length of cord doesn't change, so

(l11)+(l2 + δ2)+(l3 + δ2) = l1+l2+l3

So, δ1=2δ2
 
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