How Does Changing the Length of a Meter Stick Affect Its Oscillation Period?

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The discussion revolves around two physics problems involving oscillation and spring dynamics. The first problem involves a meter stick oscillating with a period of 6.18 seconds when hung from a thin wire and asks for the new period after cutting it to 68.1 cm. Participants clarify that the wire is stationary and the meter stick is balanced at its center while being twisted. The second problem concerns a person jumping onto a fire net, which stretches, and seeks to calculate the additional stretch when the person lies in it, emphasizing the need to account for the initial stretch in calculations. The conversation highlights the importance of understanding the setup and forces involved in both scenarios.
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2 Questions, pretty stumped on both.
A meter stick is hung at its center from a thin wire (see part (a) of the figure below).

Meter stick is hanging from a string, and being "rotated clockwise.


It is twisted and oscillates with a period of 6.18 s. The meter stick is sawed off to a length of 68.1 cm. This piece is again balanced at its center and set in oscillation (b). With what period does it oscillate?

Not really even sure where to start on this one... still looking at it.

Next:A 56.8 kg person jumps from a window to a fire net 21.8 m below, which stretches the net 1.25 m. Assume that the net behaves like a simple spring, and calculate how much it would stretch if the same person were lying in it.

Tried mgh = .5kx^2, then used F/k=x, but this didn't work, any ideas?
 
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squib said:
2 Questions, pretty stumped on both.
A meter stick is hung at its center from a thin wire (see part (a) of the figure below).

Meter stick is hanging from a string, and being "rotated clockwise.


It is twisted and oscillates with a period of 6.18 s. The meter stick is sawed off to a length of 68.1 cm. This piece is again balanced at its center and set in oscillation (b). With what period does it oscillate?

Not really even sure where to start on this one... still looking at it.

Next:A 56.8 kg person jumps from a window to a fire net 21.8 m below, which stretches the net 1.25 m. Assume that the net behaves like a simple spring, and calculate how much it would stretch if the same person were lying in it.

Tried mgh = .5kx^2, then used F/k=x, but this didn't work, any ideas?

We need a better idea what the first problem is. Does the thin wire have some length, and does it move in the problem? Is the point of contact bwteen the meter stick and the wire stationary?

Your second problem sounds like you have the right idea. Did you include the stretch in your h?
 
Good call on that second one, forgot to add h from stretch.

On the first one. The wire is stationary, no length given. The meter stick is hung by the middle, and a force is applied to make it spin in a plane horizontal to the ground, at least that is my understanding of the problem.

Any ideas?
 
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