How Does Charge Redistribution Affect Forces in a Triangular Sphere System?

AI Thread Summary
The discussion focuses on calculating the electrostatic forces between three identical conducting spheres arranged in an equilateral triangle. Initially, the charges on the spheres are given, and the first force between spheres A and C is calculated as 3.28 x 10^-6 N. The process involves connecting spheres A and B, grounding B, and then connecting B and C to redistribute charges. After grounding, sphere B's charge becomes zero, affecting the final charges on spheres B and C. The next steps require recalculating the forces between the spheres based on the new charge distributions.
Shatzkinator
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Homework Statement



In the figure 21-40, three identical conducting spheres form an equilateral triangle of side length d = 24.0 cm. The sphere radii are much smaller than d and the sphere charges are qA = -3.45 nC, qB = -3.91 nC, and qC = +6.09 nC. (a) What is the magnitude of the electrostatic force between spheres A and C? The following steps are taken: A and B are connected by a thin wire and then disconnected; B is grounded by the wire, and the wire is then removed; B and C are connected by the wire and then disconnected. What now are the magnitudes of the electrostatic force (b) between spheres A and C and (c) between spheres B and C?
http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c21/fig21_41.gif



Homework Equations


F = kq1q2/r^2


The Attempt at a Solution



I got 3.28 x 10^-6 N for part A... not sure what to do for B and C
 
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Shatzkinator said:
... not sure what to do for B and C

Follow the subsequent steps. When A and B are connected what charge ends on each? Then B is rounded so the charge on B is now 0. Now B and C are connected and you end up with how much charge on B and C?

Now it looks like you're back to calculating forces again.
 
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