How Does Current Affect Spring Extension in a Magnetic Field?

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To determine the current in the wire, apply the principles of electromagnetism and spring mechanics. The force exerted by the spring when stretched 1 cm is calculated using F = -kx, yielding a force of 0.2 N. The force on the current-carrying wire in the magnetic field is given by F = ILB, where B is 0.5 T and the length of the wire is 0.2 m. Setting the forces equal, 0.2 N = I * 0.2 m * 0.5 T, allows for solving the current I, resulting in I = 2 A. The final answer indicates that a current of 2 A is required to stretch the spring by 1 cm in the given magnetic field.
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I have the following problem on which I am unsure how to proceed.

A spring with a spring constant K = 20 N/m is shown below. It is stretched 1 cm from its equilibrium position when a current I passes through the wire. How big is the current in the wire?

The magnetic field is coming out of the page and is B = .5T, the length of the area is 20cm.
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| || | 20 cm
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You'll need to know the force on a current-carrying wire in a magnetic field: F = ILB, assuming the field is perpendicular to the wire. And you'll need to know about springs: F = -kx.
 
Thanks

Thanks alot
 

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