How Does Destructive Interference Occur at Point Q in a Double-Slit Experiment?

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Destructive interference at point Q in a double-slit experiment occurs when the path difference between light waves from slits S1 and S2 is an odd multiple of half wavelengths. This means that if the path difference is equal to (m + 1/2)λ, where m is a non-negative integer, destructive interference will result. The original poster expressed confusion about the concept and the diagram, indicating that the path from the point source to the screen at Q involves varying lengths. A reminder was given to clarify that the condition for destructive interference relies on specific wavelength relationships. Understanding these principles is essential for analyzing interference patterns in such experiments.
foxtrot2
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Hello! I'm new here, and this is my first post. I hope I have not breached any rules, but here's a rather strange (in my limited intelligence) question I encountered. I shall try to explain the question because I am unable to reproduce the diagram.

Two identical narrow slits S1 and S2 are illuminated by light of wavelength (lambda) from a point source P.

[diagram = So, P (on the left) is connected to the line marked S1 and S2 by two lines l1 and l2. l1 is longer than l2. A point Q on the right of the line S1S2 is connected to S1 by l3 and S2 by l4, l3being longer than l4]

The light is allowed to fall on a screen (at Q), and if m is a positive integer, the condition for destructive interference at Q is that...

Thanks for the help!

EDIT: Crap, I just realized this is in the wrong thread... I really apologise for bungling up my first post and the inconvenience I have caused.
 
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Show us what you have tried already. Remember, for destructive interference the path difference must be equal to 1/2 or 3/2 or 5/2 or 7/2 etc wavelengths.
 
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