How Does Distance Affect Image Formation in Convex Lenses?

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Homework Help Overview

The discussion revolves around the behavior of image formation in convex lenses as the distance between the lens and the object changes. Participants are exploring the relationship between object distance, image distance, and focal points in the context of lens optics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to understand why the image distance changes as the lens is moved away from the object. Questions are raised about the relevance of lens formulae and the focal point in explaining this behavior.

Discussion Status

Several participants have provided insights into the mathematical relationships governing lens behavior, including references to lens formulae. There is an ongoing exploration of how these relationships apply to the observed phenomena, with no explicit consensus reached yet.

Contextual Notes

Participants note that the discussion is theoretical and lacks specific numerical solutions. The nature of the homework constraints is implied but not explicitly stated.

fromthepast
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Homework Statement



I did an experiment with a convex lens, object, and image. As the lens moved farther and farther away from the object, the image decreased its distance (to remain in focus) from the object as well up to a certain point. After that point, as the lens increased its distance from the object, the image had to increase its distance from the object as well to keep in focus.

Why is this?

Homework Equations



N/A

The Attempt at a Solution



It's a theoretical question with no exact solution.
 
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fromthepast said:

Homework Statement



I did an experiment with a convex lens, object, and image. As the lens moved farther and farther away from the object, the image decreased its distance (to remain in focus) from the object as well up to a certain point. After that point, as the lens increased its distance from the object, the image had to increase its distance from the object as well to keep in focus.

Why is this?

Homework Equations



N/A

The Attempt at a Solution



It's a theoretical question with no exact solution.

One could say that it happens that way because that is the way a lens behaves.

The mathematical summaries of the situations with a lens [the lens formulae] indicate this behaviour - especially if you look at the right formula.

What lens formulae do you know?
 
1/f = 1/s + 1/s'

m = h'/h = -s'/s

Does it have something to do with the focal point?
 
fromthepast said:
1/f = 1/s + 1/s'

m = h'/h = -s'/s

Does it have something to do with the focal point?

I would like to say yes to that.
Do you know the formula using the distances from the focal points rather than from the lens?
 
Both the object distance and the image distance are measured from the lens. The object and the real image are at opposite sides of the lens, so the object and the image are d=s+s' distance from each other. The image distance is s'=d-s. Plug in for s' into the lens equation, and find d in terms of the object distance s. Investigate the function, plot it. You will see, it has a minimum.

ehild
 

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