How Does Friction Affect a Rotating Disk on an Inclined Plane?

AI Thread Summary
The discussion centers on the direction of the frictional force acting on a rotating disk on an inclined plane, particularly when the disk is moving up or down. It clarifies that static friction acts in the direction necessary to provide the observed acceleration, while kinetic friction opposes motion. When the disk moves up, friction acts opposite to its motion to decrease angular momentum, while moving down, friction aids in increasing speed. The torque affecting the disk's rotation is influenced by both weight and static friction, depending on the point of contact considered. Ultimately, the relationship between angular velocity and acceleration determines whether the disk speeds up or slows down on the incline.
mmainak
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Actually I am a bit confused with the direction of the frictional force acting on a rotating disk on an inclined plane.

I need to find the direction of frictional force on the rotating disk both the cases when it is going up and coming down under the action of an impulsive force applied on it which made it climb through a distance along the inclined plane.


The Attempt at a Solution



In my knowledge, if no friction acting in between them the disk would simply rotate at the same place. When we apply friction it's free rotation is obstructed and it will move on the plane while the friction is actually acting in direction of its motion.

So for a rotating disk friction acts along the motion.
But when I check the answer of the problem it is given that while it is going up the friction will act opposite to it's motion to decrease it's angular momentum.


I need a bit clarification in this regard.
 

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The drawing you posted is misleading. Frictional force (or any other force for that matter) does not increase or decrease angular velocity. You need a torque to change the angular velocity. The net torque about the cylinder axis is out of the screen regardless of whether the cylinder is rolling up or down hill.

I think that you are confusing static friction (what you have in this case) with kinetic friction. Kinetic friction opposes the motion but static friction is in whatever direction is necessary to provide the observed acceleration.
 
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why then rotation of the disk decreases and stops at a time while it crawls up? As you said, rotating body doesn't change the angular momentum of its own, only if some external torque applied on it .Which force is supplying this torque??
 
If you calculate the torque about the point of contact, the only force that produces a torque is the weight. If you calculate the torque about the center of the cylinder, the only force that produces a torque is static friction.

Regardless of which of the two you pick, the torque will be out of the screen and so will the angular acceleration.

If the angular velocity is also out of the screen, this means that the cylinder is rolling down hill (counterclockwise). The speed will be increasing because the angular acceleration and the angular velocity are in the same direction.

If the angular velocity is into the screen, this means that the cylinder is rolling up hill (clockwise). The speed will be decreasing because the angular acceleration and the angular velocity are in opposite directions.
 
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