How Does Friction Affect Tension in a Pulley System?

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Friction plays a critical role in the tension dynamics of the pulley system described, where block B rests on block A, and both are affected by the static friction coefficient between them. The absence of friction between block A and the tabletop allows for the movement of A and B as a single unit, provided the tension in the string is appropriately balanced with the frictional force. The largest mass that block C can have without causing block B to slide off block A is determined by the relationship between the tension, the static friction force, and the gravitational force acting on block C. The equations derived indicate that the tension must counteract both the weight of block C and the frictional force between blocks A and B. Understanding these interactions is essential for solving the problem accurately.
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Hi You guys, my first post on here. I'm having a bit of a hard time getting my head around Tension and friction, so am hoping for a little help, which would be much appreciated!

Homework Statement



Block B rests on block A, which in turn is on a horizontal tabletop. There is no friction between A and the tabletop, but the coefficient of static friction between A and B is u_s < 1. A massless string connects A to a block C. The string passes over a frictionless and massless pulley, and block C is suspended from the other end.
f.jpg


a) draw the free-body diagrams for A+B, B and C, ( if A and B moves together )

b) what is the largest mass C can have so that A and B still slide together when the system is released from rest.?

Homework Equations





The Attempt at a Solution


I've drawn the free body diagrams, and trying to find a expression for m_C. But am a bit stuck. If there had been no friction bewteen A and B, B would have slid of when the system is released, so somehow the friction plays into this.
I also know that T is equal for both A and C.
And that A+B moves along the x-axis and C on the y-axis, whic means there is no a_y for A+B and no a_x for C. As they are connected they both move with the same acceleration, so far so good.

My initial thought is :

T = m_a+b*a - f and
T = w_c ( Newtons 3.law, block c works on the string and the string works on block C)

and from there say
m_a+b*a - f = m_c *g (g=a)

-->

m_a+b - f/g = m_c

am I completely on the wrong track??
 
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The answer must contain \mu_s and the mass of B.

The forces on C are simply the weight mC and the tension upward by the string.

The tension pulls on A and B.

A, B and C must accelerate together as a single mass if B is to remain stationary with respect to A.

What is the friction between B and A? How does that relate to the acceleration of A+B+C.
 
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