FrankPlanck
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Hi all, this is the problem:
A galaxy shows a rotation curve with a given velocity v(r).
r is the distance from the center, c is the speed of light and r_{c} = 1 kpc is constant.
I have to find:
1) the mass density profile of the galaxy \rho(r)
2) the total mass M
3) Since mass/luminosity is constant M/L = 2 what is the radius of the sphere that contains half total luminosity of the galaxy
v(r)=c \sqrt{r/(r^2+r_{c}^2)}
I try...
1)
from Newton
\frac{v(r)^2}{r} = G \frac{M(r)}{r^2}
hence
\frac{G M(r)}{r} = \frac{r c^2}{r^2+r_{c}^2}
hence
M(r) = \frac{c^2}{G}\ \frac{r^2}{r^2+r_{c}^2}
and so
\rho (r) = \frac{M(r)}{V(r)} = \frac{c^2}{G}\ \frac{1}{(r^2+r_{c}^2)(4/3 \pi r)}
I could rewrite it, but it doesn't really matter.
2)
From point 1)
M(r) = \frac{c^2}{G}\ \frac{r^2}{r^2+r_{c}^2}
hence
M_{tot} = \frac{c^2}{G}\ \int^R_0 \frac{dr}{1+ \frac{r_{c}^2}{r^2}}
I don't know... damn integral...
3)
I need point 2)I'm not a native speaker, so I apologize for any possible misunderstanding.
Thank you!
Homework Statement
A galaxy shows a rotation curve with a given velocity v(r).
r is the distance from the center, c is the speed of light and r_{c} = 1 kpc is constant.
I have to find:
1) the mass density profile of the galaxy \rho(r)
2) the total mass M
3) Since mass/luminosity is constant M/L = 2 what is the radius of the sphere that contains half total luminosity of the galaxy
Homework Equations
v(r)=c \sqrt{r/(r^2+r_{c}^2)}
The Attempt at a Solution
I try...
1)
from Newton
\frac{v(r)^2}{r} = G \frac{M(r)}{r^2}
hence
\frac{G M(r)}{r} = \frac{r c^2}{r^2+r_{c}^2}
hence
M(r) = \frac{c^2}{G}\ \frac{r^2}{r^2+r_{c}^2}
and so
\rho (r) = \frac{M(r)}{V(r)} = \frac{c^2}{G}\ \frac{1}{(r^2+r_{c}^2)(4/3 \pi r)}
I could rewrite it, but it doesn't really matter.
2)
From point 1)
M(r) = \frac{c^2}{G}\ \frac{r^2}{r^2+r_{c}^2}
hence
M_{tot} = \frac{c^2}{G}\ \int^R_0 \frac{dr}{1+ \frac{r_{c}^2}{r^2}}
I don't know... damn integral...
3)
I need point 2)I'm not a native speaker, so I apologize for any possible misunderstanding.
Thank you!
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