How Does Resistance and EMF Affect Energy Transfer in a Circuit?

AI Thread Summary
The discussion revolves around calculating energy transfer and dissipation in a circuit with a wire resistance of 5.0 Ω and a battery with an emf of 2.0 V and internal resistance of 1.0 Ω. The user initially struggles to find the current, ultimately determining it to be 0.333 A using the formula i=E/(R+r). They successfully calculate that 80 J of energy is transferred from chemical to electrical form in the battery. After some confusion with power calculations, the user resolves their issues independently. The thread concludes with the user indicating they have found the solution.
justine411
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Homework Statement



A wire of resistance 5.0 Ω is connected to a battery whose emf ε is 2.0 V and whose internal resistance is 1.0 Ω. In 2.0 min, how much energy is (a) transferred from chemical to electrical form in the battery, (b) dissipated as thermal energy in the wire, and (c) dissipated as thermal energy in the battery?


Homework Equations



P=iV
P=i^2r
P=iE(the fancy E)
Vb-Va=(E/(R+r))R
i=E/(R+r)


The Attempt at a Solution



I am having trouble finding the current, so I cannot find power.
I am using i=2.0V/(5.0+1.0)=0.333A
then I get Vb-Va=(0.333Ax5.0)
the answer for part a) is 80J
when I use P=iV I don't get that answer...

If I could make it more clear...I can, just post!
 
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nevermind, I figured it out on my own

BOARD CLOSED
 

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Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
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