How Does Solar Radiation Pressure Affect an Object in Space?

AI Thread Summary
Solar radiation pressure on a reflective object in space can be calculated using the formula p = W(1+p)/c, where W is the radiation flux and c is the speed of light. The radiation flux decreases with distance from the Sun, following the inverse square law, which allows for adjustments based on the distance from the Sun. The temperature and radius of the Sun are provided to calculate flux using black body radiation principles. The force exerted on the object is determined by multiplying the pressure by the area of the reflective surface, with reflectivity assumed to be close to 1. Understanding these calculations is essential for determining the object's displacement over time due to solar radiation pressure.
mithil03
Messages
9
Reaction score
0
The question I have is:
Assume a 100 kg reflective load with 1m2 area at a distance of 1 million kilometers from
the surface of the sun. If the sun’s temperature is 6000K and radius is 695,000 km, find
the radiation pressure exerted on the object. Find how far the load would be from its
initial position after 10 days assuming it started at rest.

I went through the internet and found that
p= W (1+p)/c
Where p – pressure
c – speed of light, 3 ·108 m/sec
W – radiation flux (near the Earth ~1400 W/m2, so-called solar constant
p – overall surface reflectance (from 0 to 1)

But i couldn't relate the Flux value for other distances, and Why would they give the Temperature and radius of the sun ?
Help please..
 
Physics news on Phys.org
Ok, flux drops as 1/R^2, where R is the distance from the sun. So in order to find flux at some distance R, you can take flux at Earth, WE, and use this formula:

W_R = W_E\frac{R_E^2}{R^2}

Where RE is distance of Earth from the Sun.

The reason they give temperature and radius of the Sun is because there is another way to find the flux using black body radiation.

W_R = \sigma T^4 \frac{R_S^2}{R^2}

Where T is temperature of the Sun, RS is radius of the Sun, R is the distance at which you want to find flux, and sigma is Stefan-Boltzman constant:

\sigma = 5.67 \times 10^{-8} W m^{-2} K^{-4}
 
Last edited:
Thanks a lot K^2. Understood this now. Could you help me with the next part of the problem please..
 
You already have the formula. Force is pressure times area of the reflector. I'm guessing reflectivity is assumed to be close to 1, so your formula reads P = 2*W/c. That's all you need.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top