my first reply was "a drunken post", just to clear up this query further
When pressure is exerted on a liquid, whether through the introduction of an inert gas or by direct porous piston, the vapor pressure increases. Pressure is applied to the liquid, more gases escape.
The relation to surface curvature is in which one considers the variation of the pressure due to surface tension with the curvature of a particular liquid. A droplet of water for instance, experiences an internal pressure as well as an external pressure, along with surface tension, which acts to shrink the droplet, and can be equated with the external pressure. This additional "external pressure" serves to increase the vapor pressure (compared to that of a bulk liquid).
the equation to remember is
[tex]p=p*e^{ \frac{Vm \Delta P}{RT} }[/tex] where the [tex]\Delta P[/tex] pertains to the change in the total pressure experienced by a liquid.