How Does Temperature Affect the Diameter of a Hole in an Aluminum Plate?

AI Thread Summary
The discussion focuses on calculating how temperature changes affect the diameter of a hole in an aluminum plate. For Part A, the diameter at 199 degrees Celsius was successfully determined using the linear expansion formula. In Part B, the user correctly manipulated the equation to find the final temperature when the diameter is 1.177 cm, using the initial diameter and temperature values. The method applied for Part B is confirmed to be correct. Understanding the relationship between temperature and material expansion is crucial for accurate calculations.
Brit412
Messages
24
Reaction score
0

Homework Statement


A hole in an aluminum plate has a diameter of 1.179 cm at 22.00 degrees Celsius.
Part A asks for the diameter of the hole at 199 degrees Celsius.?
Part B asks for the temperature of the hole when its diameter is 1.177 cm?


Homework Equations



∆L = alpha L(0) ∆T

The Attempt at a Solution


I got the answer for Part A.

Here's what I did so far for Part B:
I manipulated the equation as follows:
∆L/alpha*L(0) + Temp (initial) = Temp (final)

And I used the difference between 1.177 and 1.179 cm for ∆L, used 1.179 for L(0) and the 22 degrees C for the initial temperature. Is this method correct?
 
Physics news on Phys.org
yes.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top