How Does Touching a Violin String Affect Its Frequency?

AI Thread Summary
Touching a violin string at L/3 creates a node, effectively dividing the string into two segments. The tension and mass of the string remain constant, allowing for the calculation of the lowest frequency produced. The fundamental frequency can be determined using the formula f1 = 1/2L sqrt[F/μ], where μ is the mass per unit length. The new length for frequency calculation is 0.22m, which corresponds to the longer segment of the string. This approach confirms the correct understanding of how touching the string alters its vibrational characteristics.
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[SOLVED] Violin String and Waves

1. A violin string of length 0.33m and mass 50g is under a tension of 40N. A violin player touches the string a distance L/3 from one end, which produces a node at that point. What is the lowest frequency that can now be produced on the string?
2. I have several equations but they involve the funamental frequency
3. I tried solving this problem using the equation f1= 1/2L sqrt[F/mew] where mew is the mass per unit length. For the L i used 0.33- 0.33/3 to get 0.22m. This is the part I am not sure about. Is this the new length or is something else up. Thanks!b]
 
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There are effectively two strings now, with the same T/mew ratio. The lowest note would be the fundamental harmonic of the longer portion.
 
great, so i did it right. Thanks!
 
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