How Fast Do a Hockey Puck and Octopus Slide After Collision?

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A 0.105 kg hockey puck traveling at 35.0 m/s collides with a 0.240 kg octopus, and they slide off together. The discussion emphasizes the conservation of linear momentum, stating that the initial momentum of the puck and octopus equals their final momentum together. To find their combined velocity, one must calculate the total mass and apply the momentum formula: M_puck*v_puck + M_oct*v_oct = M_total*v_final. The conversation blends humor with physics concepts, highlighting the fun in solving such problems. The focus remains on understanding the physics behind the collision.
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A 0.105 kg hockey puck, moving at 35.0 m/s, strikes a 0.240 kg octopus thrown onto the ice by a hockey fan. The puck and octopus slide off together. Find their velocity in m/s

I really do not have a clue on what to do and how to do it.
 
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I'd think that the octopus will throw the puck at the offending fan, seeing that he was to blame in the first place, to get the poor octopus get hit by the puck. With the force of eight arms behind it, it'll pack a pretty punch. Serves him right.

Getting back to Physics, the sum of the initial momenta of puck and poor octopussy will be equal to the final momentum of the two together. You know initial masses and speeds, and the total mass, so it shouldn't be problem.
 
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Yeah, we get some pretty weird descriptions, but it makes it fun.

So basically I add the two masses and then find the impusle of the puck hitting the octopus and then I multiply that by the two masses?
 
M_puck*v_puck + M_oct*v_oct = Mtotal*v_final.

That's conservation of linear momentum.
 
Thanks for your help. I knew it was something like that.
 
An octopus?

Good grief.

http://www.turboconnection.com/images/picard.jpg
 
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