How Fast Must a Volleyball Be Served to Clear the Net and Land Inbounds?

  • Thread starter Thread starter noeinstein
  • Start date Start date
  • Tags Tags
    Magnitude
AI Thread Summary
To determine the required serve speed in women's volleyball, the net height is 2.24 m and the player serves from a height of 3.05 m, needing to clear a horizontal distance of 8.3 m. The minimum initial velocity for the ball to clear the net is calculated using the formula V(o)=R x sqrt(g/2h), where h is the height difference of 0.81 m. The calculated minimum velocity is approximately 16.54 m/s. Additionally, the maximum velocity must ensure the ball lands within the back line after crossing the net. Accurate calculations are essential for effective serving strategies in volleyball.
noeinstein
Messages
14
Reaction score
0

Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?




Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
 
Physics news on Phys.org
noeinstein said:

Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?

Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
Mostly correct, but V(o)=R x sqrt(g/(2h))

or v_0\,=\,R\sqrt{\frac{g}{2h}}
 
Thank you much sir for your time!
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top