How Fast Must a Volleyball Be Served to Clear the Net and Land Inbounds?

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To determine the required serve speed in women's volleyball, the net height is 2.24 m and the player serves from a height of 3.05 m, needing to clear a horizontal distance of 8.3 m. The minimum initial velocity for the ball to clear the net is calculated using the formula V(o)=R x sqrt(g/2h), where h is the height difference of 0.81 m. The calculated minimum velocity is approximately 16.54 m/s. Additionally, the maximum velocity must ensure the ball lands within the back line after crossing the net. Accurate calculations are essential for effective serving strategies in volleyball.
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Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?




Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
 
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noeinstein said:

Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?

Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
Mostly correct, but V(o)=R x sqrt(g/(2h))

or v_0\,=\,R\sqrt{\frac{g}{2h}}
 
Thank you much sir for your time!
 
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