How Is Angular Momentum Calculated in Particle Motion?

AI Thread Summary
To calculate the angular momentum of a particle in motion, the momentum vector is derived by multiplying the mass by the velocity vector. The cross product of the position vector and the momentum vector is then computed to find angular momentum. In this case, the calculated angular momentum was -23.9 kg*m^2/s, which is incorrect because magnitudes cannot be negative. The discussion highlights the importance of understanding that angular momentum is a pseudo-vector with both magnitude and direction, but only the magnitude was required for this problem. The participant realized their mistake regarding the sign of the answer and acknowledged the common nature of such errors.
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Homework Statement



A 1.47kg particle moves in the xy plane with a velocity of v = (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is r = (1.35i + 2.57j)m.


Homework Equations



p = mv

L = r x p (the x is supposed to be a cross product and not a variable)

L = r x mv

The Attempt at a Solution



First I scaled the velocity vector: v = (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.

Then I took the cross product of the r vector with the new momentum vector:
(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)

The answer I got was -23.9 kg*m^2/s, which wasn't right.

What did I do wrong? Am I even anywhere near the correct solution/answer?
 
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thehiggsboson said:

Homework Statement



A 1.47kg particle moves in the xy plane with a velocity of v = (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is r = (1.35i + 2.57j)m.


Homework Equations



p = mv

L = r x p (the x is supposed to be a cross product and not a variable)

L = r x mv

The Attempt at a Solution



First I scaled the velocity vector: v = (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.

Then I took the cross product of the r vector with the new momentum vector:
(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)

The answer I got was -23.9 kg*m^2/s, which wasn't right.

What did I do wrong? Am I even anywhere near the correct solution/answer?

Did you specify the direction of the angular momentum? (It's a pseudo-vector, so it has a magnitude and direction).
 
I didn't, but I just went back and tried it and it picked up the k as being part of the unit. So, it's not that, I don't think. The question also just asks for magnitude.
 
thehiggsboson said:
I didn't, but I just went back and tried it and it picked up the k as being part of the unit. So, it's not that, I don't think. The question also just asks for magnitude.
Okay, just the magnitude. What answer did you type in for that?
 
-23.9 kg*m^2/s
 
Are magnitudes ever negative?
 
Nope. Wow, I feel a little stupid now. Thanks!
 
thehiggsboson said:
Nope. Wow, I feel a little stupid now. Thanks!

Heh. We've all been there, done that, got the T-shirt. Cheers.
 

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