How Is Friction Affecting the Motion of a Block on a Horizontal Surface?

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The discussion revolves around calculating the frictional force acting on a 3.52 kg block being pulled on a horizontal surface with a force of 12.6 N at an angle of 31 degrees. The coefficient of kinetic friction is given as 0.04, which is essential for determining the frictional force using the formula fk = µkFn. Participants suggest that the user may be overlooking the fundamental equation F = ma, which is crucial for calculating the block's acceleration while considering friction. The conversation emphasizes the need to account for the retarding force of friction in these calculations. Understanding these concepts will help in solving the problem effectively.
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Homework Statement


A 3.52 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=12.6N at an angle theta=31.0degrees above the horizontal. The floor has a coefficient of kinetic friction µk = 0.04, what is the magnitude of the frictional force on the block when the block is moving? There is a second part which is What is the magnitude of the acceleration of the block when friction is being considered? Although I think I am forgetting forumals or something. If someone can just send me along the right track I think I can figure it out. Thanks!

m = 3.52
F= 12.6
Theta = 31 degrees
µk = 0.04

Homework Equations



Sine and cosine functions.
µkFn= fk

The Attempt at a Solution



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You mean you think you are missing F = ma?

(Less of course the correction you will need to make for the retarding force of friction.)
 

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