SS2006
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kownig that work = f X d
if tehres friction acting as well, for example 1500 N opposing a cart moving up along a path 800M long, the cart is 120Kg.
normally work would be = 120(9.8) X 800 right
but here it'll be more cause we have to add the work needed to overcome friction ofcoruse
so where does the 1500N go, so we can find total work
if tehres friction acting as well, for example 1500 N opposing a cart moving up along a path 800M long, the cart is 120Kg.
normally work would be = 120(9.8) X 800 right
but here it'll be more cause we have to add the work needed to overcome friction ofcoruse
so where does the 1500N go, so we can find total work