How Is Phase Difference Calculated Between Two Sound Waves?

AI Thread Summary
To calculate the phase difference between two sound waves from speakers 3.79 meters apart, with a listener 65.6 meters away, the wavelength must first be determined using the frequency of 4010 Hz and the speed of sound at 343 m/s. The wavelength is found to be approximately 0.0856 meters. The path difference between the two waves reaching the listener can then be calculated based on their distances, which leads to the phase difference formula ΔΦ = (2π/λ) * Δd, where Δd is the path difference. The discussion emphasizes the importance of understanding superposition and how the distance affects the phase relationship of the waves. Ultimately, the phase difference can be calculated using these principles.
jrrodri7
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Homework Statement


Two Loud speakers are placed on a wall 3.79 meters apart. A listener stands directly in front of one of the speakers, 65.6 meters from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4010 Hz The speed of sound in Air is 343 m/s. What is the phase difference \Delta\Phi between the two waves? (answer in radians)


Homework Equations


y = A sin (kx (+/-) \omegat


The Attempt at a Solution


I tried finding the wavelength and using trig to find the distance between the observer and speakers...but I'm not sure if it has anything to do with the problem, and I haven't gotten an answer out of this yet...I'm lost. The only thing I know is superposition, but I know that if you just add sin to sin, you don't just get sin, and I don't know how to derive that to see how that works...

HELP!
 
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jrrodri7 said:

Homework Statement


Two Loud speakers are placed on a wall 3.79 meters apart. A listener stands directly in front of one of the speakers, 65.6 meters from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4010 Hz The speed of sound in Air is 343 m/s. What is the phase difference \Delta\Phi between the two waves? (answer in radians)

Homework Equations


y = A sin (kx (+/-) \omegat

The Attempt at a Solution


I tried finding the wavelength and using trig to find the distance between the observer and speakers...but I'm not sure if it has anything to do with the problem, and I haven't gotten an answer out of this yet...I'm lost. The only thing I know is superposition, but I know that if you just add sin to sin, you don't just get sin, and I don't know how to derive that to see how that works...

HELP!

Sure it does. The difference in distance is going to determine what lag there is between the 4010 hz sound waves.
 

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