How Is the Average Resistance Force Calculated for a Diver Entering Water?

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To calculate the average resistance force exerted on a diver entering water, the potential energy (PE) of the diver is first determined to be 10,290 J based on his weight and the height of the dive. The next step involves calculating the deceleration of the diver as he comes to rest 5 meters below the surface. Without a given velocity, the discussion emphasizes the need to apply the formula F = ma, where 'm' is the mass of the diver and 'a' is the deceleration. The calculation requires understanding the forces acting on the diver during the descent and the subsequent stop in the water. This approach will lead to determining the average resistance force experienced by the diver.
johny_doe
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A 70 kg diver steps off a 10m tower and drops straight down into the water. If he comes to rest 5m below the surface determine the average resistance force exerted on him by the water.


I can determine that the PE should be 10290 J. But I'm stuck for what exactly to do next... Since there's no velocity given I am lost.
 
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F = ma, find his deceleration.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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