How Is the Force on a Helium Ion Calculated in a Magnetic Field?

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SUMMARY

The force experienced by a He2+ ion traveling at a velocity of 1.3 × 10^5 m/s in a magnetic field of 0.42 T is calculated using the formula F = qvBsinθ. In this case, the charge of the helium ion is confirmed to be 2 × 1.6 × 10^-19 C, resulting in a force calculation of F = 2 × 1.6e-19 × 1.3e5 × 0.42. The angle θ is assumed to be 90 degrees, maximizing the force experienced by the ion.

PREREQUISITES
  • Understanding of Lorentz force equation: F = qvBsinθ
  • Knowledge of ion charge states, specifically for He2+
  • Familiarity with basic physics concepts of magnetic fields
  • Ability to perform scientific notation calculations
NEXT STEPS
  • Explore the implications of varying angles θ in the Lorentz force equation
  • Learn about the behavior of ions in magnetic fields in plasma physics
  • Investigate the applications of magnetic fields in particle accelerators
  • Study the properties of helium ions and their interactions in different environments
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Students and educators in physics, particularly those focusing on electromagnetism and ion behavior in magnetic fields.

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Homework Statement


What is the magnitude of the force experienced by a He2+ ion traveling with v = 1.3 × 10^5i m/s in a magnetic field B = 0.42 j T?

Homework Equations


F=qvbsinθ

The Attempt at a Solution


F=2*1.6e-19*1.3e5*0.42

I am unsure about the charge on the Helium ion.

Is it 2*1.6e-19?
 
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Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...
 
Geofleur said:
Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...

So the charge is 2*1.6e-19?
 
Yep.
 

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