How Is the Horizontal Distance of a Cannon Ball Calculated on a Sloped Surface?

AI Thread Summary
The discussion focuses on calculating the horizontal distance a cannonball travels when fired from a slope. The formula provided for this distance is dx = 2v²cos(o)sin(O+o)/gcos(O), where o is the firing angle, v is the initial velocity, and O is the slope angle. Key equations discussed include the sine addition formula and the kinematic equation for distance. Participants suggest considering the intersection of the projectile's trajectory with the slope's equation for accurate calculations. The conversation emphasizes the importance of understanding the relationship between angles and distances in projectile motion.
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A cannon ball is fired from an angle o with an intial velocity of v. The hill sklopes down with an angle of O. Prove that the horizontal distance the cannon ball travels is given by dx= 2v2cos(o)sin(O+o)/gcos(O)



2. Equations
sin(O+o)=sin(O)cos(o)+sin(o)cos(O)
d=1/2gt2




The Attempt at a Solution


Please help me! Hopefully the picture helps!
 

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Welcome to PF.

You might want to consider the point at which it hits as the intersection of the function that describes the projectile's flight with the equation that describes the slope of the incline.

For instance for 45 degrees you know that dx = dy.

Or more generally for angle θ you have Dy = tanθ *dx
 
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