How Is the Mass of a Kart Represented in a Force vs. Acceleration Graph?

AI Thread Summary
The discussion focuses on interpreting the force vs. acceleration graph of a kart with a mass of 0.6485 kg. The slope of the graph is 0.5586 N/m/s², while the intercept is 0.2097 N. The question raised is whether the mass of the kart is represented in both the slope and the intercept or just the slope. It is noted that in an ideal scenario, the intercept should be zero, leading to inquiries about the significance of the nonzero intercept. The conversation emphasizes the relationship between force, mass, and acceleration, as described by the equation F=ma.
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I have a graph of force vs. acceleration of a kart on a a ramp that i manually pushed back and forth with my hand.

The mass of the the kart is .6485kg and when i did the linear fit it said that slope of the graph was .5586N/m/s^2 and the intercept .2097 N

My question is would i see the mass of the kart represented in both the slope and the intercept or just the slope?

I know the F=ma and in a perfect setting with not other forces the intercept should be 0.
 
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my linear equation would be Force = .5586N/m/s^2(a) + .2097N
 
You should offer your own opinion first.
How do you interpret the nonzero intercept?
 

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