How Is the Total Energy of Photons Calculated in Electron-Positron Collisions?

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Homework Help Overview

The discussion revolves around calculating the total energy of photons resulting from a collision between a positron and an electron, both traveling at high speeds. The problem involves concepts from relativistic physics, specifically energy calculations in particle collisions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of energy using relativistic equations, including the Lorentz factor (γ) and rest energy (mc²). There are attempts to clarify the need for including both kinetic and rest mass energy in the total energy calculation. Questions arise regarding the use of energy units (Joules vs. eV) and the necessity of including rest mass in the energy summation.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's calculations and reasoning. Some guidance has been offered regarding the importance of total energy in the context of photon production, but there is still confusion about the correct formulation and the role of rest mass energy.

Contextual Notes

Participants note that the problem specifically asks for the energy in Joules, and there is mention of potential constraints from homework guidelines regarding the approach to solving the problem. Additionally, there is uncertainty about the instructor's emphasis on including rest mass energy in the calculations.

magma_saber
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Homework Statement


Suppose that a positron traveling at a speed of 0.93c collides head on with an electron traveling at the same speed.

What is the sum of the energies of the two photons?


Homework Equations


mass of an electron = 9e-31 kg
E=\gammamc2 - mc2


The Attempt at a Solution


2.2032e-13 - 8.1e-14 = 1.3932e-13
1.393e-13 * 2 = 2.7864e-13 J
 
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I have a few comments:

It's kind of hard to follow what you are doing. Including units with all values in your equations would help with that.

I don't see where or if you have calculated γ.

Also, it's probably easier to work in eV energy units, rather than Joules. Your textbook might even give the value of mc2 for the electron, in eV units.
 
the questions ask for in Joules.

rest energy = mc2
(9e-31)*(3d8)2 = 8.1e-14

\gamma = 1/\sqrt{1-(0.93)^2} = 2.72

particle energy = \gamma*mc2
(2.72)*(9e-31)*(3d8)2 = 2.20e-13

E = particle energy - rest energy
E = 2.20e-13 - 8.1e-14 = 1.39e-13

Then i multiplied it by 2 since that is the energy of one of the particle.
1.39e-13*2 = 2.79e-13 J
 
magma_saber said:
the questions ask for in Joules.
Okay, understood.

rest energy = mc2
(9e-31)*(3d8)2 = 8.1e-14

\gamma = 1/\sqrt{1-(0.93)^2} = 2.72

particle energy = \gamma*mc2
(2.72)*(9e-31)*(3d8)2 = 2.20e-13
Looks good.
E = particle energy - rest energy
E = 2.20e-13 - 8.1e-14 = 1.39e-13
Here E is the kinetic energy of one of the particles. However, it is the total particle energy, kinetic and rest mass, that ultimately is converted into the photons.

Then i multiplied it by 2 since that is the energy of one of the particle.
Yes, but you'll need to use the total energy rather than only kinetic. Looks good otherwise.
 
Redbelly98 said:
Okay, understood.Looks good.

Here E is the kinetic energy of one of the particles. However, it is the total particle energy, kinetic and rest mass, that ultimately is converted into the photons.Yes, but you'll need to use the total energy rather than only kinetic. Looks good otherwise.

I have a similar problem and I followed the posters procedure but I am however confused as to why we need to add rest mass as the instructor has said. If someone would clarify this problem in better detail much appreciated.

I am just confused, is the final formula:
2(RE + KE + PE + Mass) = Total Energy of the two photons?
 

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