How Large is x(t) at Maximum Acceleration for an Oscillating Block?

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The discussion revolves around determining the displacement x(t) of an 18.0-kg block at maximum acceleration during its oscillation. The block's displacement is described by the equation x(t) = (17.0 cm) cos[(22.0 rad/s) t + π rad]. It is clarified that maximum acceleration occurs when the displacement x(t) reaches its peak value. The maximum displacement, therefore, is 17 cm, as indicated in the original equation. This conclusion highlights the relationship between maximum acceleration and maximum displacement in oscillatory motion.
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Homework Statement


A 18.0-kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x(t) = (17.0 cm) cos[( 22.0 rad/s) t + π rad]

What is the magnitude of x(t) when the block experiences its maximum acceleration?

Homework Equations


most are below

The Attempt at a Solution


i started to work backwords and solve for k but after that I am lost since i thought k is what i should be solving for

nm just realized it gave it to me in the problem you can delete this
 
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What is the magnitude of x(t) when the block experiences its maximum acceleration?
When the acceleration is maximum, x(t) is maximum i.e. a
 


ya the original eq had it as the very first term it was 17cm
 
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