How Large Should the Second Tank Be to Achieve the Desired Pressure Increase?

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To raise the pressure in a volume of 1760 cubic inches from 16PSI to 40PSI using a second tank with a maximum pressure of 100PSI, the required volume of the second tank must be calculated. The ideal gas law can be applied, as pressure (PSI) relates to force per unit area. Clarification is needed on whether the gas from the second tank will mix with the first volume and if the temperature is assumed constant during this process. Understanding these parameters is essential for determining the appropriate size of the second tank. Accurate calculations will ensure the desired pressure increase is achieved efficiently.
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Homework Statement


The pressure in a volume of 1760 cubic inches needs to be raised from 16PSI to 40PSI. This is done via a second tank which has a maximum pressure of 100PSI. In order for this system to function, the second volume needs to be of a certain size. Calculate the volume required for tank.


Homework Equations


Not sure.


The Attempt at a Solution


I am stuck on how I can use PSI which is a measurement of pressure for an area with volume.
Any suggestions on where I could start would be greatly appreciated, as I am truly stuck.

Many thanks,
pavadrin
 
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You would use the pressure in the ideal gas law. The unit, PSI, is pounds per square inch; one atmosphere pressure is close to 14.7 PSI. (Pressure always has units which involve area, since it is defined as the force per area on a surface.)

The problem is a bit unclear on one point. Is the gas in the second tank going to be released into the first volume, so that it mixes with it to raise the pressure? Is it assumed that the temperature remains constant while this happens?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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